Question 4.18: Determine the potential distribution within the two adjacent...
Determine the potential distribution within the two adjacent triangular regions if the potential is specified at all nodes
V_{1} = 8 @ ( 4, 0); V_{2} = 0 @ (0, 0); V_{3} = 0 @ (4, 3); and V_{4} = 8 @ (0, 3).

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The voltage distribution in the triangle (1, 2, 3) was determined in Example 4-17 to be V_{1,2,3}^{(e)} (x,y) = 2x – (8/3 )y. The potential distribution within the adjacent triangle (2, 3, 4) is
V_{2,3,4}^{(e)} (x,y) = [1 x y] \left[\begin{matrix} 1 &0 &0 \\1& 4 & 3 \\ 1& 0 & 3\end{matrix} \right] ^{-1} \left[\begin{matrix}0 \\ 0 \\ 8 \end{matrix} \right]= [1 x y ]\left[\begin{matrix} 1 & 0 & 0 \\ 0&1/4& -1/4 \\ -1/3& 0 &1/3\end{matrix} \right] \left[\begin{matrix}0 \\ 0 \\ 8 \end{matrix} \right] \\= [1 x y ] \left[\begin{matrix} 0\\ -2 \\8/3 \end{matrix} \right] = -2x +\frac{8}{3} yRelated Answered Questions
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