Question 11.15: Determine the reactions at the supports for the prismatic be...

Determine the reactions at the supports for the prismatic beam and loading shown (Fig. 11.50).

11.50
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The beam is statically indeterminate to the first degree. We consider the reaction at A as redundant and release the beam from that support. The reaction R _{A} is now considered as an unknown load (Fig. 11.51) and will be determined from the condition that the deflection y_{A} at A must be zero. By Castigliano’s theorem y_{A}=\partial U / \partial R_{A}, where U is the strain energy of the beam under the distributed load and the redundant reaction. Recalling Eq. (11.70), we write

x_{j}=\frac{\partial U}{\partial P_{j}}=\int_{0}^{L} \frac{M}{E I} \frac{\partial M}{\partial P_{j}} d x                            (11.70)

 

y_{A}=\frac{\partial U}{\partial R_{A}}=\int_{0}^{L} \frac{M}{E I} \frac{\partial M}{\partial R_{A}} d x                             (11.87)

We now express the bending moment M for the loading of Fig. 11.51.

The bending moment at a distance x from A is

M=R_{A} x-\frac{1}{2} w x^{2}                            (11.88)

and its derivative with respect to R_{A} is

\frac{\partial M}{\partial R_{A}}=x                          (11.89)

Substituting for M and \partial M / \partial R_{A} from (11.88) and (11.89) into (11.87), we write

y_{A}=\frac{1}{E I} \int_{0}^{L}\left(R_{A} x^{2}-\frac{1}{2} w x^{3}\right) d x=\frac{1}{E I}\left(\frac{R_{A} L^{3}}{3}-\frac{w L^{4}}{8}\right)

 

Setting y_{A}=0 and solving for R_{A}, we have

R_{A}=\frac{3}{8} w L                            R_{A}=\frac{3}{8} w L \uparrow

From the conditions of equilibrium for the beam, we find that the reaction at B consists of the following force and couple:

R _{B}=\frac{5}{8} w L \uparrow                        M_{B}=\frac{1}{8} w L^{2}\circlearrowright

11.51

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