Determine the reinforcement requirements for a 6 -in. ID nozzle that is located at the junction of a cylindrical shell and a hemispherical head. The entire opening is in the cylindrical shell, but the reinforcement extends in both directions - some into the head and some into the shell. The ID of

Question

Determine the reinforcement requirements for a 6 -in. ID nozzle that is located at the junction of a cylindrical shell and a hemispherical head. The entire opening is in the cylindrical shell, but the reinforcement extends in both directions - some into the head and some into the shell. The ID of the shell is 41.875 in. The allowable stress of all material is 17.5 ksi. The design pressure is 700 psi at a design temperature of 500°F. All joints are fully radiographed with a joint efficiency of E = 1.0. There is no corrosion.

Accepted Answer

1 . The minimum required thickness of the cylindrical shell from Example 11.7 is

t = 0.858 in.; use 1 in.

2 . The minimum required thickness of the head is

[latex]t_{h}=\frac{P L}{2 S E-0.2 P}=\frac{700 imes 20.938}{2 imes 17,500 imes 1-0.2 imes 700}=0.420 ext { in. }[/latex]; use 1 in.

3 . The minimum required thickness of the nozzle is

[latex]t_{n}=\frac{\operatorname{Pr}}{S E-0.6 P}=\frac{700 imes 3}{17,500 imes 1-0.6 imes 700}=0.123 ext { in. }[/latex]; use [latex]\frac{3}{4}[/latex] in.

4 . Limits parallel to vessel surface, whichever is the larger of

d = 6 in.

or

[latex]T_{s}+T_{n}+0.5 d=1+0.75+3=4.75 ext { in. }[/latex]; use 6 in.

5 . Limits perpendicular to vessel surface, whichever is the smaller of

[latex]2.5 T_{s}=2.5(1)=2.5 ext { in. }[/latex]

or

[latex]2.5 T_{n}=2.5(0.75)=1.875 ext { in. }[/latex]; use 1.875 in.

6 . Reinforcement area required by Eq. 11.20 is

[latex]A_{2}=2\left(T_{n}-t_{n} ight)\left(2.5 T_{n}+T_{e} ight)[/latex] (11.20)

[latex]A_{r}=d t_{r} F=6(0.858)(1.0)=5.148 ext { in. }^{2}[/latex]

7 . Reinforcement area available in shell and head by Eq. 11.21 is

[latex]A=d t_{r} F[/latex] (11.21)

[latex]A_{11}=\left(E T_{s}-F t_{r} ight)=(1-0.858)(6-3)=0.852 ext { in. }^{2}[/latex]

[latex]A_{12}=\left(E T_{h}-F t_{h} ight)=(1-0.420)(6-3)=1.740 ext { in. }^{2}[/latex]

8 . Reinforcement area available in nozzle wall by Eq. 11.23 is

[latex]A_{1}=2\left(T_{s}+T_{n}+0.5 d ight)-d\left(E T_{s}-F t_{r} ight)[/latex] (11.23)

[latex]A_{2}=5 T_{n}\left(T_{n}-t_{r n} ight)=5(0.75)(0.75-0.123)=2.351 ext { in. }^{2}[/latex]

9 . Total reinforcement available from shell, head, and nozzle is

[latex]A_{t}=A_{11}+A_{12}+A_{2}=4.943 ext { in. }{ }^{2}[/latex]; not enough

10 . Reinforcement area available in attachment fillet weld assuming leg dimension of 0.5 in. is

[latex]A_{3}=(0.5)^{2}=0.250 ext { in. }^{2}[/latex]

11 . Total including attachment fillet welds is

[latex]A_{t}=5.193 ext { in. }{ }^{2}>A_{r}=5.148 ext { in. }^{2}[/latex]

Question 11.8: Determine the reinforcement requirements for a 6 -in. ID noz...

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