Question 15.8: Determining Activation Energy The reaction 2N2O5(g) → 4NO2(g...

Determining Activation Energy
The reaction

  2  N_{2}O_{5} (g)   →   4  NO_{2}  (g) + O_{2}  (g) 

was studied at several temperatures and the following values of k were obtained:

k  ( s ^{- 1 } ) T  (° C )
2.0  ×  10 ^{-5} 20
7.3   ×  10 ^{-5} 30
2.7   ×  10 ^{-4} 40
9.1   ×  10 ^{-4} 50
2.9    ×  10 ^{-3} 60

Calculate the value of   E_{a}   for this reaction.

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To obtain the value of   E_{a} , we need to construct a plot of \ln (k) versus 1/T. First, we must calculate values of \ln (k) and 1/T:

T  ( ° C) T  ( K ) 1 / T  ( K ) k  (s ^{-1}) \ln (k)
20 293 3.41    ×  10 ^{-3} 2.0  ×  10 ^{-5} – 10.82
30 303 3.30    ×  10 ^{-3} 7.3  ×  10 ^{-5} – 9.53
40 313 3.19   ×  10 ^{-3} 2.7   ×  10 ^{-4} – 8.22
50 323 3.10    ×  10 ^{-3} 9.1   ×  10 ^{-4} – 7.00
60 333 3.00    ×  10 ^{-3} 2.9    ×  10 ^{-3} – 5.84

The plot of  \ln (k) versus 1/T is shown in Fig. 15.14 ▼. The slope is found to be  – 1.2 × 10^{4}   K. Since

Slope  =  –  \frac{E_{a}}{R}

then

  E_{a} =  – R (slope )  =  –  (8.3145  J  K ^{-1}    mol^{-1})  (- 1.2 × 10^{4}  K)

= 1.0  × 10^{5}  J / mol

Thus the value of the activation energy for this reaction is 1.0  × 10^{5}  J / mol

1514

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