Question 9.10: Discuss the convergence properties of the two series (i) ∑si...
Discuss the convergence properties of the two series
(i)∑n2sinnx, (ii)∑nsinnx.
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(i) Since |sin nx| ≤ 1 for all x∈R and ∑n21 is convergent, the series ∑n2sinnx is uniformly convergent on R by the M test.
(ii) If ∣∣∣nsinnx∣∣∣≤Mn for all x in some interval I, then Mn≥nc, where c=x∈Isup∣sinnx∣>0. Since ∑n1 is divergent, we see that the M-test is not applicable on any interval in R. We shall use the Dirichlet test to prove uniform convergence on any interval [a,b]⊆(2mπ,(2m+1)π), m∈Z. The proof relies on the equality
k=1∑nsinkx=2sin21xcos21x−cos(n+21)x, x=2mπ,m∈Z, (9.16)
which can be proved by induction on n. Setting uk(x)=sinkx and Un(x)=Σk=1n uk(x), we see that
∣Un(x)∣≤2∣sin21x∣∣cos21x∣+∣cos(n+21)x∣
≤∣sin21x∣1
≤max{∣sin21a∣1,∣sin21b∣1} for all n∈N, x∈[a,b].
With vn(x)=1/n on [a, b], we obtain a decreasing sequence which converges (uniformly) to 0. By Dirichlet’s test the series ∑nsinnx converges uniformly on [a, b].
Using Fourier expansions (see [CAR], for example), it can be shown that ∑nsinnx converges pointwise on R to a function which is periodic in 2π, and which is defined on [−π, π] by
S(x)=⎩⎪⎪⎨⎪⎪⎧−2π+x,0,2π−x,x∈[−π,0)x=0x∈(0,π].
Note that x=2mπ, m∈Z, are points of (jump) discontinuity for the function S. Hence the series ∑nsinnx of continuous terms cannot converge uniformly in any interval containing such points.