Question 10.10: Draw an MO energy diagram and determine the bond order for t...
Draw an MO energy diagram and determine the bond order for the N_{2}^{-} ion. Would you expect the bond to be stronger or weaker than in the N_{2} molecule? Is N_{2}^{-} diamagnetic or paramagnetic?
| Write an energy-level diagram for the molecular orbitals in N_{2}^{-}. Use the energy ordering for N_{2}. |  |
| The N_{2}^{-} ion has 11 valence electrons (5 for each nitrogen atom plus 1 for the negative charge). Assign the electrons to the molecular orbitals beginning with the lowest energy orbitals and fol lowing Hund’s rule. |  |
| Calculate the bond order by subtracting the number of electrons in antibonding orbitals from the number in bonding orbitals and dividing the result by two. | N_{2}^{-} bond order =\frac{8-3}{2}=+2.5 |
| The bond order is 2.5, which is a lower bond order than in the N_{2} molecule 1bond order = 32; therefore, the bond is weaker. The MO diagram shows that the N_{2}^{-} ion has one unpaired electron and is therefore paramagnetic. | |
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