Question 8.14: Draw the Lewis structure of xenon tetrafluoride (XeF4).
Draw the Lewis structure of xenon tetrafluoride (XeF4).
Strategy Follow the steps for drawing Lewis structures. The skeletal structure is
Setup There are 36 total valence electrons (eight from Xe and seven from each of the four F atoms).
We subtract eight electrons to account for the bonds in the skeleton, leaving 28 to distribute. We first complete the octets of all four F atoms. When this is done, four electrons remain, so we place two lone pairs on the Xe atom.
The blue check mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.
Learn more on how we answer questions.
Related Answered Questions
Question: 8.16
Verified Answer:
[4(414 kJ/mol) + 2(498.7 kJ/mol)] - [2(799 kJ/mol)...
Question: 8.15
Verified Answer:
Following the procedure outlined on page 314, we g...
Question: 8.8
Verified Answer:
The formal charges are as follows: +1 (N atom), -1...
Question: 8.9
Verified Answer:
Of the two possible arrangements, the structure on...
Question: 8.12
Verified Answer:
:\overset{..}{\underset{..}{I} } - \overset...
Question: 8.4
Verified Answer:
(a) The difference between the electronegativities...
Question: 8.1
Verified Answer:
(a) [ :\overset{..}{\underset{..}{F}}:[/lat...