Question 9.SP.2: Electrolyte Concentration The laboratory tests for Michelle ...

Electrolyte Concentration

The laboratory tests for Michelle indicate that she has hypercalcemia with a blood calcium level of 8.8 mEq/L. How many moles of calcium ion are in 0.50 L of her blood?

The blue check mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.

STEP 1 State the given and needed quantities.

ANALYZE THE
PROBLEM
Given Need Connect
0.50 L, 8.8 mEq of
Ca2+/L
moles of Ca2+ 1 Eq = 1000 mEq,

1 mole of Ca2+ = 2 Eq of Ca2+

STEP 2 Write a plan to calculate the moles.

\overset{liters  of}{\underset{solution}{}}    \overset{Electrolyte}{\underset{concentration}{}}    \overset{milliequivalents}{\underset{of  Ca^{2+}}{}}    \overset{Metric}{\underset{factor}{}}    \overset{equivalents}{\underset{of  Ca^{2+}}{}}     Eq/mole    \overset{moles}{\underset{of  Ca^{2+}}{}}

STEP 3 State the equalities and conversion factors.

\begin{matrix} \begin{matrix}1  L  of solution  =  8.8  mEq  of  Ca^{2+} & 1  Eq  =  1000  mEq \\ \frac{8.8  mEq  Ca^{2+}}{1  L  solution}    and    \frac{1  L  solution}{8.8  mEq  Ca^{2+}} & \frac{1000  mEq  Ca^{2+}}{1  Eq  Ca^{2+}}    and    \frac{1  Eq  Ca^{2+}}{1000  mEq  Ca^{2+}}\end{matrix} \\ \\ \begin{matrix} 1  mole  of  Ca^{2+}  =  2  Eq  of  Ca^{2+}                                                                                                            \\ \frac{2  Eq  Ca^{2+}}{1  mole  Ca^{2+}}    and    \frac{1  mole  Ca^{2+}}{2  Eq  Ca^{2+}}                                                                                                        \end{matrix} \end{matrix}

STEP 4 Set up the problem to calculate the number of moles.

\begin{matrix}\underset{Two  SFs}{\underset{}{0.50  \cancel{L}}} \times \overset{Two  SFs}{\overset{}{\underset{Exact}{\underset{}{\frac{8.8  \cancel{mEq  Ca^{2+}}}{1  \cancel{L}}}}}} \times \overset{Exact}{\overset{}{\underset{Exact}{\underset{}{\frac{1  \cancel{Eq  Ca^{2+}}}{1000  \cancel{mEq  Ca^{2+}}}}}}} \times \overset{Exact}{\overset{}{\underset{Exact}{\underset{}{\frac{1  mole  Ca^{2+}}{2  \cancel{Eq  Ca^{2+}}}}}}} = \underset{Two  SFs}{\underset{}{0.0022  mole  of  Ca^{2+}}}\end{matrix}

Related Answered Questions

Question: 9.PP.101

Verified Answer:

A solution with a high salt (solute) concentration...