Question 7.2: Estimate the alpha particle flux from an Al2O3 package conta...
Estimate the alpha particle flux from an Al_2O_3 package containing 1 ppm U^{238} per gram of ceramic. Assume that only 25% of the alphas generated escape the package from a depth of 14 \mu m or less, and that the density of Al_2O_3 is 3.9 g/cm^3.
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In 1 \ cm^3 of Al_2O_3 there are 1 \times 10^{-6} \times 1 \ cm^{3} \times 3.9 \ g/cm^3=3.9 \times 10^{-6}g of U^{238} . This corresponds to 6.85 \times 10^{-7}Ci/g \times 3.9 \times 10^{-6}g/cm^3=2.67 \times 10^{-12}Ci/cm^3 , or an equivalent radiation flux of 2.67 \times 10^{-12}Ci/cm^3 \times 14 \times 10^{-4}cm=3.74 \times 10^{-15}Ci/cm^3.
Collecting terms, 8 \alpha P/dis \times 0.25 \times (3.74 \times 10^{-15}Ci/cm^2)\times (2.2 \times 10^{12}dpm/Ci) \times 60 min/h=0.98 \alpha P/cm^2-h
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