Question AE.1: Finding Normality Find the normality of a solution containin...

The formula mass of ascorbic acid (C_{6}H_{8}O_{6}) is 176.124. In 6.34 g, there are (6.34 \cancel{g})/(176.124  \cancel{g}/mol) = 3.60 × 10^{−2} mol. Because each mole contains 2 equivalents in this example, 6.34 g = (2 equiv/\cancel{mol}) (3.60 × 10^{−2}  \cancel{mol}) = 7.20 × 10^{−2} equivalent. The normality is (7.20 × 10^{−2} equiv)/(0.250 L) = 0.288 N.