Question 10.2.5: Finding the equation for a circle Write the equation for the...
Finding the equation for a circle
Write the equation for the circle that has center (4, 5) and passes through (-1, 2).
The radius is the distance from (4, 5) to (-1, 2):
r=\sqrt{(4-(-1))^{2}+(5-2)^{2}}=\sqrt{25+9}=\sqrt{34}Use h = 4, k = 5, and r=\sqrt{34} in (x-h)^{2}+(y-k)^{2}=r^{2} to get the equation
(x-4)^{2}+(y-5)^{2}=34.
Related Answered Questions
Question: 10.4.6
Verified Answer:
We have A=21, B=-10 \sqrt{3} , an...
Question: 10.4.5
Verified Answer:
Since y = 1/x is equivalent to xy - 1 = 0, we have...
Question: 10.4.3
Verified Answer:
Use the rotation equations x^{\prime}=x \c...
Question: 10.3.3
Verified Answer:
The graph that we seek is the graph of
\fr...
Question: 10.3.2
Verified Answer:
Divide each side of the equation by 36 to get the ...
Question: 10.2.4
Verified Answer:
The graph of this equation is a translation of the...
Question: 10.2.2
Verified Answer:
To sketch the ellipse, we find the x-intercepts an...
Question: 10.1.3
Verified Answer:
First use x = -b/(2a) to find the x-coordinate of ...
Question: 10.5.4
Verified Answer:
Convert to rectangular coordinates as follows:
[la...
Question: 10.5.3
Verified Answer:
From the previous theorem we have e = 1, p = 3, an...