Question 14.1: FINDING THE PERFORMANCE OF A SEPARATELY EXCITED MOTOR CONTRO...

FINDING THE PERFORMANCE OF A SEPARATELY EXCITED MOTOR CONTROLLED BY A DC–DC CONVERTER

The armature of a separately excited DC motor is controlled by a DC–DC converter operating at a frequency of f_{c} = 1 kHz and a duty cycle of k = 0.8. The DC–DC supply voltage to the armature is V_{s} = 220 V. The field current is also controlled by a DC–DC converter operating at a frequency of f_{s} = 1 kHz and a duty cycle of δ = 0.5. The DC supply voltage to the field is V_{f} = 280 V. The motor parameters are:

Armature resistance, R_{m} = 0.1 Ω
Armature inductance, L_{m} = 10 mH
Field resistance, R_{f} = 10 Ω
Field inductance, L_{f}= 20 mH
Back-emf constant, K = 0.91
Viscous torque constant, B = 0.3
Motor inertia, J = 1
Load torque, T_{L} = 50, 100, and 150 N⋅m

Use PSpice to plot the transient response of the armature and field current, the
torque developed, and the motor speed for a duration of 0 to 30 msec in steps of
10 μsec.

The blue check mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.

The armature and field circuits for PSPice simulation are shown in Figure 14.1(a) and Figure 14.1(b), respectively. The net torque, which is obtained by subtracting the viscous (T_{B}) and load torque (T_{L}) from the torque developed (T_{d}), is integrated to obtain the motor speed as shown in Figure 14.1(c). The motor speed is integrated to obtain the shaft position as shown in Figure 14.1(d).

The PSpice schematic is shown in Figure 14.2, which comprises three separate blocks: the motor field, motor armature, and motor load consisting of inertia J and viscous torque constant B. It has one pulse-width modulated (PWM) generator for the armature control and one PWM generator for the motor field control. The listing of the circuit file is as follows:

Example 14.1 DC separately excited motor with variable load torques

SOURCE     VS 1 0 DC 220V             ; Armature supply

PARAM Duty_a=0.5    ; duty cycle of the armature circuit
.PARAM Duty_f=0.8    ; duty cycle of the field circuit
.PARAM Freq=1kHz     ; switching frequency
.PARAM Km=0.1
Vg1 6 0 PULSE (0 20V 0 1ns 1ns {{Duty_a}/{Freq}-2ns}
{1/{Freq}}
Vg2 11 0 PULSE (0 20V 0 1ns 1ns {{Duty_f}/{Freq}-2ns}
{1/{Freq}}
Rg1 6 0 10MEG
VF 7 0 DC 280V              ; Field supply
Rg2 11 0 10MEG

CIRCUIT      .PARAM VISCOUS = 0.3  ; Viscous constant

.PARAM J = 1 ; Motor inertia
.PARAM TL = 100 ; Load torque
.STEP PARAM TL 50 150 50 ; Load torque varied
S1 1 2 6 0 SMOD ; Voltage-controlled switch
.MODEL SMOD VSWITCH (RON=0.01 ROFF=10E+6 VON=10V
VOFF=5V)
D1 0 2 DMOD
.MODELDMODD (IS=2.2E−15 BV=1200V CJO=0 TT=0) ; Diode
model parameters
RM 2 3 0.1
LM 3 4 10MH
VX 4 5 DC 0V                   ; Senses the armature current
E1 5 0 VALUE = {{km} *V(17) *I(VY)}
RF 8 9 10
LF 9 10 20MH
VY 10 0 DC 0V                   ; Senses the field current
S2 7 8 11 0 SMOD              ; Voltage-controlled switch
D2 0 8 DMOD
E2 12 13 VALUE = {{km} *I(VX) *I(VY)} ; Torque developed
VL 14 13 {TL}                      ; Load torque
E3 0 14 VALUE = {VISCOUS*V (17)} ; Viscous torque
D3 12 15 DMOD
Rg 15 0 1G
G1 0 16 15 0 1                      ; Net torque
VZ 16 17 DC 0V                  ; Measures the net torque
C1 17 0 {J} IC=0V               ; Load inertia
Rc1 17 0 1G
G2 0 18 17 0 1                      ; Velocity to position
C2 18 0 1 IC=0V
Rc2 18 0 1G

ANALYSIS   . TRAN 10US 30MS UIC        ; Transient analysis with

initial condition
. PLOT TRAN V(3) V(1)           ; Prints on the output file
. OPTIONS ABSTOL = 1.00N RELTOL = 0.01 VNTOL = 0.1
ITL5 = 50000
. PROBE                                    ; Graphics post-processor

      . END

The plots of the transient response for the armature I(VX) and field currents I(VY) are shown in Figure 14.3. The plots for the torque developed V(12,13) and the motor speed V(17) are shown in Figure 14.4. The field current shown has not reached steady-state conditions. The armature current reaches a peak before settling down. The torque is pulsating because of pulsating armature and field currents.

14.1(a)
14.1(b)
14.1(c)
14.1(d)
14.2
14.3
14.4

Related Answered Questions