Question 3.5: For a gas described by the van der Waals equation of state, ...

For a gas described by the van der Waals equation of state, P=nRT/(Vnb)an2/V2P =nRT/\left( V-nb \right)-an^{2}/V^{2}. Use this equation to complete these tasks: a. Calculate (U/V)T\left(\partial U/ \partial V\right)_{T} using (U/V)T=T(P/T)VP\left(\partial U/ \partial V\right)_{T}=T\left( \partial P/\partial T \right)_{V}-P. b. Derive an expression for the change in internal energy, ΔUT=ViVf(U/V)TdV\Delta U_{T}=\int_{V_{i}}^{V_{f}}\left( \partial U/\partial V \right)_{T}dV, in compressing a van der Waals gas from an initial molar volume ViV_{i} to a final molar volume VfV_{f} at constant temperature.

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a. T(PT)VP=T([nRTVnbn2αV2]T)VP=nRTVnbPT\left( \frac{\partial P}{\partial T} \right)_{V}-P=T\left( \frac{\partial \left[ \frac{nRT}{V-nb}-\frac{n^{2}\alpha}{V^{2}} \right]}{\partial T} \right)_{V}- P= \frac{nRT}{V-nb}- P

=nRTVnbnRTVnb+n2αV2=n2αV2= \frac{nRT}{V-nb}- \frac{nRT}{V-nb}+\frac{n^{2}\alpha}{V^{2}}=\frac{n^{2}\alpha}{V^{2}}

 

b. ΔUT=ViVf(UV)TdV=ViVfn2αV2dV=n2α(1Vi1Vf)\Delta U_{T}=\int_{V_{i}}^{V_{f}}\left( \frac{\partial U}{\partial V} \right)_{T}dV =\int_{V_{i}}^{V_{f}}\frac{n^{2}\alpha}{V^{2}}dV=n^{2}\alpha\left( \frac{1}{V_{i}}-\frac{1}{V_{f}} \right)

Note that ΔUT\Delta U_{T} is zero if the attractive part of the intermolecular potential is zero.

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