Question 3.7: For an AT8051 and DSC89C4x0 system of 11.0592 MHz, find how ...

The 8051 Microcontroller and Embedded Systems

For an AT8051 and DSC89C4x0 system of 11.0592 MHz, find how long it takes to execute each instruction.
(a) MOV R3,#55 (b) DEC R3 (c) DJNZ R2 target
(d) LJMP (e) SJMP (f) NOP (g) MUL AB

The blue check mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.

AT8051 DS89C4x0

(a) 1×1085ns ＝ 1085ns 2×90ns = 180ns
(b) 1×1085ns ＝ 1085ns 1×90ns = 90ns
(c) 2×1085ns ＝ 2170ns 4×90ns = 360ns
(d) 2×1085ns ＝ 2170ns 3×90ns = 270ns
(e) 2×1085ns ＝ 2170ns 3×90ns = 270ns
(f) 1×1085ns ＝ 1085ns 1×90ns = 90ns
(g) 4×1085ns ＝ 4340ns 9×90ns = 810ns

Related Answered Questions

Question: 3.1

Find the period of the machine cycle for 11.0592 MHz crystal frequency ...

Verified Answer:

11.0592/12 = 921.6 kHz; machine cycle is 1/921.6 k...

Question: 3.6

Find the period of the machine cycle (MC) for various versions of 8051, if XTAL=11.0592 MHz. (a) AT89C51 (b) P89C54X2 (c) DS5000 (d) DS89C4x0 ...

Verified Answer:

(a) 11.0592MHz/12 = 921.6kHz; MC is 1/921.6k...

Question: 3.5

Find the size of the delay in following program, if the crystal frequency is 11.0592MHz. Machine Cycle DELAY: MOV R2,#200 1 AGAIN: MOV R3,#250 1 HERE: NOP 1 NOP 1 DJNZ R3,HERE 2 DJNZ R2,AGAIN 2 RET 2 ...

Verified Answer:

For HERE loop, we have (4x250) x1.085 μs＝1085μs. ...

Question: 3.4

Find the size of the delay in following program, if the crystal frequency is 11.0592MHz. Machine Cycle DELAY: MOV R3,#250 1 HERE: NOP 1 NOP 1 NOP 1 NOP 1 DJNZ R3,HERE 2 RET 2 ...

Verified Answer:

The time delay inside HERE loop is [250 ( 1 + 1 + ...

Question: 3.3

Find the size of the delay in following program, if the crystal frequency is 11.0592MHz. MOV A,#55H AGAIN: MOV P1,A ACALL DELAY CPL A SJMP AGAIN ;—time delay——- DELAY: MOV R3,#200 HERE: DJNZ R3,HERE RET ...

Verified Answer:

Machine cycle DELAY: MOV R3,#200 ...

Question: 3.2

For 8051 system of 11.0592 MHz, find how long it takes to execute each instruction. (a) MOV R3,#55 (b) DEC R3 (c) DJNZ R2 target (d) LJMP (e) SJMP (f) NOP (g) MUL AB ...

Verified Answer:

Machine cycles Time to execute (a) 1 1x1.085μs ...