Question 9.2: For the data in Table 9.1, compute SSTr and SSE.
For the data in Table 9.1, compute SSTr and SSE.
TABLE 9.1 Brine II hardness of welds using four different fluxes | |||||||
Flux | Sample Values | Sample Mean | Sample Standard Deviation |
||||
A | 250 | 264 | 256 | 260 | 239 | 253.8 | 9.7570 |
B | 263 | 254 | 267 | 265 | 267 | 263.2 | 5.4037 |
C | 257 | 279 | 269 | 273 | 277 | 271.0 | 8.7178 |
D | 253 | 258 | 262 | 264 | 273 | 262.0 | 7.4498 |
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The sample means arc presented in Table 9.1. They are
\bar{X}_{1 .}=253.8 \quad \bar{X}_{2 .}=263.2 \quad \bar{X}_{3 .}=271.0 \quad \bar{X}_{4 .}=262.0
The sample grand mean was computed in Example 9.1 to be \bar{X}_{ \ldots}=262.5. We now use Equation (9.4) to calculate SSTr.
SSTr=\sum\limits_{i=1}^l J_i\left(\bar{X}_i-\bar{X}_{..}\right)^2 (9.4)
\text{SSTr} =5(253.8-262.5)^2+5(263.2-262.5)^2+5(271.0-262.5)^2+5(262.0-262.5)^2 \\ \qquad \ \ =743.4To compute SSE we will use Equation (9.9), since the sample standard deviations s_i have already been presented in Table 9.1.
SSE =\sum\limits_{i=1}^l\left(J_i-1\right) s_i^2 (9.9)
\text{SSE}=(5-1)(9.7570)^2+(5-1)(5.4037)^2+(5-1)(8.7178)^2+(5-1)(7.4498)^2 \\ \qquad =1023.6Related Answered Questions
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