Question 9.2: For the data in Table 9.1, compute SSTr and SSE.

For the data in Table 9.1, compute SSTr and SSE.

 TABLE 9.1 Brine II hardness of welds using four different fluxes
Flux Sample Values Sample Mean Sample Standard
 Deviation
A 250 264 256 260 239 253.8 9.7570
B 263 254 267 265 267 263.2 5.4037
C 257 279 269 273 277 271.0 8.7178
D 253 258 262 264 273 262.0 7.4498
The blue check mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.

The sample means arc presented in Table 9.1. They are

\bar{X}_{1 .}=253.8 \quad \bar{X}_{2 .}=263.2 \quad \bar{X}_{3 .}=271.0 \quad \bar{X}_{4 .}=262.0

The sample grand mean was computed in Example 9.1 to be \bar{X}_{ \ldots}=262.5. We now use Equation (9.4) to calculate SSTr.

SSTr=\sum\limits_{i=1}^l J_i\left(\bar{X}_i-\bar{X}_{..}\right)^2          (9.4)

\text{SSTr} =5(253.8-262.5)^2+5(263.2-262.5)^2+5(271.0-262.5)^2+5(262.0-262.5)^2 \\ \qquad \ \ =743.4

To compute SSE we will use Equation (9.9), since the sample standard deviations s_i have already been presented in Table 9.1.

SSE =\sum\limits_{i=1}^l\left(J_i-1\right) s_i^2            (9.9)

\text{SSE}=(5-1)(9.7570)^2+(5-1)(5.4037)^2+(5-1)(8.7178)^2+(5-1)(7.4498)^2 \\ \qquad =1023.6

Related Answered Questions