Question 18.12: For the input wave to the clipping circuit shown in Fig. 18....

For any value of V_{i n}>10 \,V, the ideal diode is forward biased and V_{\text {out }}=V_{\text {in }}-10. For example, at V_{\text {in }}=15 \,V [See Fig. 18.36 (i)], V_{\text {out }}=15-10=5 \,V.

For any value of V_{\text {in }}<10 \,V, the ideal diode is reverse biased. Therefore, circuit current is zero and hence V_{\text {out }}=0. For example, with V_{\text {in }}=5 V [See Fig. 18.36 (ii)], V_{\text {out }}=0 \text { and } V_d (drop across diode) = 5 V

The output waveform will be as shown in Fig. 18.37 (ii).