Question 13.1: Geometric Quantities of a V-Belt Drive A V belt is to operat...

Geometric Quantities of a V-Belt Drive

A V belt is to operate on sheaves of 8 and 12 in. pitch diameters (Figure 13.5a). Calculate

a. The center distance

b. The contact angle

Assumption: A B-section V belt is used, having the actual pitch length of 69.8 in. (Table 13.2).

Table 13.2
Pitch Lengths (in inches) of Standard V Belts
Cross Section
A B C A C C D E
27.3 113.3 113.8 114.9
36.3 36.8 121.3 121.8 122.9 113.3
43.3 43.8 145.8 146.9 147.3
52.3 52.8 53.9 159.8 160.9 161.3
61.3 61.8 62.9 174.8 175.9 173.3
69.3 69.8 70.9 181.8 182.9 183.3 184.4
76.3 76.8 77.9 211.8 212.9 213.3 214.5
86.3 86.8 87.9 240.3 240.9 240.8 241.0
91.3 91.8 92.9 270.3 270.9 270.8 271.0
106.3 106.8 107.9 300.3 300.9 300.8 301.0
F13.5
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a. Through the use of Equation 13.11,

b=L-\pi\left(r_1+r_2\right)=69.8-\pi(6+4)=38.38  in .

Equation 13.10 is therefore

c=\frac{1}{4}\left[b+\sqrt{b^2-8\left(r_2-r_1\right)^2}\right]     (13.10)

c=\frac{1}{4}\left[38.38+\sqrt{38.38^2-8(6-4)^2}\right]=19.09  in .

b. Applying Equation 13.7,

\phi=\pi-2 \alpha=180^{\circ}-2 \sin ^{-1}\left(\frac{150-100}{480}\right)=168^{\circ}

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