Question 2.45: Given limn→∞ zn = l. Prove that limn→∞ Re{zn} = Re{lg} and l...
Given \lim _{n \rightarrow \infty} z_n=l . Prove that \lim _{n \rightarrow \infty} \operatorname{Re}\left\{z_n\right\}=\operatorname{Re}\{l\} \text { and } \lim _{n \rightarrow \infty} \operatorname{Im}\left\{z_n\right\}=\operatorname{Im}\{l\}
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Let z_n=x_n+i y_n and l=l_1+i l_2, where x_n, y_n, and l_1, l_2 are the real and imaginary parts of z_n and l, respectively.
By hypothesis, given any \epsilon>0 we can find N such that \left|z_n-l\right|<\epsilon for n>N, i.e.,
or
\sqrt{\left(x_n-l_1\right)^2+\left(y_n-l_2\right)^2}<\epsilon \quad \text { for } n>NFrom this, it necessarily follows that
\left|x_n-l_1\right|<\epsilon \quad \text { and } \quad\left|y_n-l_2\right|<\epsilon \text { for } n>Ni.e., \lim _{n \rightarrow \infty} x_n=l_1 and \lim _{n \rightarrow \infty} y_n=l_2, as required.
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