Question 1.8: Given three resistors in parallel, where R1 = 3 Ω, R2 = 6 Ω,...

Using Equation (1.43), we obtain

1 / R_{\text {parallel-equiv }}=1 / R_1+1 / R_2+1 / R_3+\ldots+1 / R_n \text {. }                 (1.43)

\frac{1}{R_{\text {parallel-equiv }}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3} \text {, }           (1.44)

and using the corresponding values for R_{1} , R_{2} , \text{ and } R_{3}, we get that

1 / R_{\text {parallel-equiv }}=1 / 3+1 / 6+1 / 2 \text {, }          (1.45)

from where

R_{\text {equiv }}= 1  \Omega \text {. }            (1.46)