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Question 16.7: Graded When zinc is dissolved in a strong acid, zinc ions an...

GRADED

When zinc is dissolved in a strong acid, zinc ions and hydrogen gas are produced.
Zn(s)  +  2H^{+}(aq) → Zn^{2+}(aq) + H_{2}(g)
At 25°C, calculate
ⓐ ΔG°.
ⓑ ΔG when P_{H_{2}} = 750 mm Hg, [Zn^{2+}] = 0.10 M, [H^{+}] = 1.0 × 10^{-4} M.
ⓒ the pH when ΔG = -100.0 kJ, P_{H_{2}} = 0.933 atm, [Zn^{2+}] = 0.220 M and the mass of Zn is 155 g.

ANALYSIS
equation for the reaction (Zn(s)  +  2H^{+}(aq)  →  Zn^{2+}(aq)  +  H_{2}(g))

T(25°C)

Information given:
ΔG_{f}° values at 25°C (Appendix 1) Information implied
ΔG° Asked for

STRATEGY

1. Find ΔG° by substituting ΔG_{f}° values into Equation 16.3.

ΔG°_{reaction}  =  ΣΔG°_{f_{  products}}  –  ΣΔG°_{f_{  reactants}}           (16.3)

2. Recall that ΔG_{f}° for elements in their native state at 25°C and H^{+}(aq) is zero.

ANALYSIS
P_{H_{2}} (750 mm Hg); [Zn^{2+}](0.10 M); [H^{+}] (1.0 × 10^{-4} M); T(25°C) from part (a): ΔG°(-147.1 kJ) Information given:
R value in energy units Information implied
ΔG Asked for

STRATEGY

ANALYSIS
P_{H_{2}}(0.933 atm); [Zn^{2+}](0.220 M); mass Zn(155 g); T(25°C)
ΔG(-100.0 kJ)
From part (a): ΔG°(-147.1 kJ)
Information given:
R value in energy units Information implied
pH Asked for

STRATEGY

1. Find Q by substituting into Equation 16.4.

ΔG = ΔG° + RT ln Q                          (16.4)
2. Write the equation for Q.
3. Solve for [H^{+}] by substituting into the Q expression. Change [H^{+}] into pH.

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