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Question 25.12: Helium Burning Find the energy released in the reaction 3^4H...

Helium Burning

Find the energy released in the reaction 3^{4} He \rightarrow{ }^{12} C .

ORGANIZE AND PLAN As usual with nuclear reactions, the mass difference between initial and final particles is large enough that we can use E=\Delta m c^{2}   to find the energy release.

\text { Known: } M\left({ }^{4} He \right)=4.0026  u ; M\left({ }^{12} C \right)=12.0000 u ; 1  u \cdot c^{2}= 931.5 MeV.

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