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Question 9.12: How many liters of a 2.00 M NaCl solution are needed to prov...

How many liters of a 2.00 M NaCl solution are needed to provide 67.3 g of NaCl?

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STEP 1   State the given and needed quantities.

ANALYZE THE PROBLEM Given Need Connect
67.3 g of NaCl, 2.00 M NaCl solution liters of NaCl solution molar mass of NaCl, molarity

STEP 2  Write a plan to calculate the volume.

grams  of  NaCl    \boxed{Molar  Mass} →      moles  of  NaCl   \boxed{Molarity} →    liters  of  NaCl  solution

STEP 3  Write equalities and conversion factors.

\begin{array}{r c}\boxed{\begin{matrix} 1  mole  of  NaCl = 58.44  g  of  NaCl \\\frac{58.44  g  NaCl}{1  mole  NaCl } \text{ and } \frac{1  mole  NaCl }{58.44  g  NaCl} \end{matrix}} & \boxed{\begin{matrix} 1  L  of  NaCl  solution = 2.00  moles  of  NaCl \\ \frac{2.00  moles  NaCl}{ 1  L  NaCl  solution}\text{ and }\frac{1  L  NaCl  solution}{2.00  moles  NaCl} \end{matrix}}\end{array}

STEP 4  Set up the problem to calculate the volume.

67.3   \cancel{g  NaCl}     \times    \overset{Exact}{\underset{Four  SFs}{\boxed{\frac{1  \cancel{mole  NaCl}}{58.44  \cancel{ g  NaCl}} }}}   \times    \overset{Exact}{\underset{Three  SFs}{\boxed{\frac{1  L  NaCl  solution}{2.00  \cancel{ mole  NaCl}} }}} = \underset{Three  SFs}{ 0.576  L  of  NaCl  solution }

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