Question 7.17: How much heat, in kilojoules, is released when nitrogen and ...
How much heat, in kilojoules, is released when nitrogen and hydrogen react to form 50.0 g of ammonia?
N_{2}(g) + 3H_{2}(g) → 2NH_{3}(g) ΔH = -92.2 kJ
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STEP 1 State the given and needed quantities (moles).
ANALYZE THE PROBLEM | Given | Need | Connect |
50.0 g of NH_{3} | heat released, in kilojoules | ΔH = – 92.2 kJ, molar mass | |
Equation | |||
N_{2}(g) + 3H_{2}(g) → 2NH_{3}(g) |
STEP 2 Write a plan using t he heat of reaction and any molar mass needed.
grams of NH_{3} \boxed{\begin{array}{l}\text{Molar}\\\text{Mass}\end{array}} → moles of NH_{3} \boxed{\begin{array}{l}\text{Heat of}\\\text{reaction}\end{array}} → kilojoulesSTEP 3 Write the conversion factors including heat of reaction.
\begin{array}{r c}\boxed{\begin{matrix} 1 mole of NH_{3}= 17.03 g of NH_{3}\\\frac{17.03 g NH_{3}}{1 mole NH_{3}} \text{ and } \frac{1 mole NH_{3}}{17.03 g NH_{3}} \end{matrix}} & \boxed{\begin{matrix}2 moles of NH_{3} = -92.2 kj \\ \frac{-92.2 kj}{ 2 moles NH_{3}}\text{ and }\frac{2 moles NH_{3}}{-92.2 kj} \end{matrix}}\end{array}STEP 4 Set up the problem to calculate the heat.
\underset{Three SFs }{50.0 \cancel{g NH_{3}}} \times \overset{Exact}{\underset{Four SFs }{\boxed{\frac{1 \cancel{mole NH_{3}}}{17.03 \cancel{ g NH_{3}}} }}} \times \overset{Three Sfs }{\underset{Exact }{\boxed{\frac{-92.2 kJ}{2 \cancel{ moles NH_{3}}} }}} = \underset{Three Sfs }{-135 kJ}Therefore, 135 kJ are released.
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