Question 7.17: How much heat, in kilojoules, is released when nitrogen and ...

How much heat, in kilojoules, is released when nitrogen and hydrogen react to form 50.0 g of ammonia?

N_{2}(g) + 3H_{2}(g) → 2NH_{3}(g)          ΔH = -92.2 kJ

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STEP 1   State the given and needed quantities (moles).

ANALYZE THE PROBLEM Given Need Connect
50.0 g of NH_{3} heat released, in kilojoules ΔH = – 92.2 kJ, molar mass
Equation
N_{2}(g) + 3H_{2}(g) → 2NH_{3}(g)

STEP 2  Write a plan using t he heat of reaction and any molar mass needed.

grams  of  NH_{3}     \boxed{\begin{array}{l}\text{Molar}\\\text{Mass}\end{array}} →      moles  of  NH_{3}     \boxed{\begin{array}{l}\text{Heat of}\\\text{reaction}\end{array}} →    kilojoules

STEP 3  Write the conversion factors including heat of reaction.

\begin{array}{r c}\boxed{\begin{matrix} 1  mole  of  NH_{3}= 17.03  g  of  NH_{3}\\\frac{17.03  g  NH_{3}}{1  mole  NH_{3}} \text{ and } \frac{1  mole  NH_{3}}{17.03  g  NH_{3}} \end{matrix}} & \boxed{\begin{matrix}2  moles  of  NH_{3} = -92.2  kj \\ \frac{-92.2  kj}{ 2  moles  NH_{3}}\text{ and }\frac{2  moles  NH_{3}}{-92.2  kj} \end{matrix}}\end{array}

STEP 4   Set up the problem to calculate the heat.

\underset{Three  SFs }{50.0   \cancel{g  NH_{3}}}     \times    \overset{Exact}{\underset{Four  SFs }{\boxed{\frac{1  \cancel{mole  NH_{3}}}{17.03  \cancel{ g  NH_{3}}} }}}   \times    \overset{Three  Sfs }{\underset{Exact }{\boxed{\frac{-92.2  kJ}{2  \cancel{ moles  NH_{3}}} }}}    = \underset{Three  Sfs }{-135  kJ}

Therefore, 135 kJ are released.

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