Question 22.13: If R1 = 2 kΩ and R2 = 22 kΩ in Fig. 22-20, what is the outpu...

With Eq. (22-19):

V_{out}\cong \frac{R_1+R_2}{R_1} (1.25 V)               (22-19)

V_{out}= \frac{2 \ kΩ + 22 \ kΩ}{2 \ k\Omega } (1.25 V) = 15 \ V

When R_2 is increased to 46 kΩ, the output voltage increases to:

V_{out}= \frac{2 \ kΩ + 46 \ kΩ}{2 \ k\Omega } (1.25 V) = 30 \ V