Question 32.WE.3: In a particular A-scan, similar to Figure 32.26, the time in...

In a particular A-scan, similar to Figure 32.26, the time interval between pulses 1 and 2 is 12 µs. The speed of ultrasound in bone is about 4000  m  s^{−1}. Determine the thickness of the bone.

32.26
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Step 1 Determine the distance travelled by the ultrasound in the time interval of 12 µs.
distance = speed × time
distance = 4000 × 12 × 10^{−6} = 4.8 × 10^{−2}  m
Step 2 Calculate the thickness of the bone.
Hint: The distance you have just calculated must be halved because the ultrasound has to travel through the bone twice.
thickness of bone = \frac{4.8  ×  10^{−2}}{2}

= 2.4 × 10^{−2}  m (2.4 cm)

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