Question 13.24: Induced emf of AC Generator Calculate the induced emf per ph...

Electrical Engineering: Concepts and Applications

Induced emf of AC Generator

Calculate the induced emf per phase of a four-pole AC generator which has a torque of 6 N·m. The speed of the AC generator is 1500 rpm and the flux of the AC generator is 0.6 Wb. The number of turns per phase is six.

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In order to calculate the induced emf per phase of an AC generator, first find the frequency of the generator. Because the number of poles and the speed of the generator are given, using Equation (13.64):

$N_s=\frac{120 \cdot f}{P}$ (13.64)

f=\frac{N_{s} \cdot P}{120}=\frac{1500 \cdot 4}{120}=\frac{150}{3}=50  Hz

Now, calculate the induced emf per phase. Using Equation (13.67):

$E_{\text {phase}}=T \cdot E_{\text {av}}=T \cdot 4 f \phi$ (13.67)

E_{\text {phase}}=T \cdot 4 \cdot f \cdot \phi=6 \cdot 4 \cdot 50 \cdot 0.6=720  V

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