Question 9.1: Load-Line Analysis If the circuit of Figure 9.5 has VSS = 2 ...

First, we locate the ends of the load line. Substituting v_D = 0 and the values given for V_{SS} = 2 \text{ V} and R into Equation 9.5 yields i_D = 2 \text{ mA}. These values plot as point B in Figure 9.7. Substitution of i_D = 0 and circuit values results in v_D = 2 \text{ V}. These values plot as point A in the figure. Constructing the load line results in an operating point of V_{DQ}\cong 0.7 \text{ V and }I_{DQ}\cong 1.3 \text{ mA}, as shown in the figure. 

V_{ss}=Ri_D+v_D \quad \quad \quad (9.5)