Question 9.2: Load-Line Analysis Repeat Example 9.1 if VSS = 10 V and R = ...
Load-Line Analysis
Repeat Example 9.1 if V_{SS} = 10 \text{ V} and R = 10 kΩ.
When an intercept of the load line falls off the page, we select a point at the edge of the page.
If we let v_D = 0 and substitute values into Equation 9.5, we find that i_D = 1 \text{ mA}. This is plotted as point C in Figure 9.7.
V_{ss}=Ri_D+v_D \quad \quad \quad (9.5)
If we proceed as before by assuming that i_D = 0, we find that v_D = 10 \text{ V}. This is a perfectly valid point on the load line, but it plots at a point far off the page. Of course, we can use any other point satisfying Equation 9.5 to locate the load line.
Since we already have point C on the i_D axis, a good point to use would be on the right-hand edge of Figure 9.7. Thus, we assume that v_D = 2 \text{ V} and substitute values into Equation 9.5, resulting in i_D = 0.8 \text{ mA}. These values plot as point D. Then, we can draw the load line and find that the operating-point values are V_{DQ} \cong 0.68 \text{V and } I_{DQ} \cong 0.93 \text{ mA}.
