Question 4.10: Moles How many moles of sodium ions, Na^+, are in 5.63 g of ...
Moles
How many moles of sodium ions, \text{Na}^{+}, are in 5.63 g of sodium sulfate, \text{Na}_{2}\text{SO}_{4}?
Strategy
The formula weight of \text{Na}_{2}\text{SO}_{4} is 2(23.0) + 32.1 + 4(16.0) = 142.1 amu. In the conversion of grams \text{Na}_{2}\text{SO}_{4} to moles, we use the conversion factors 1 mol \text{Na}_{2}\text{SO}_{4} = 142.1 g \text{Na}_{2}\text{SO}_{4} and 1 mole \text{Na}_{2}\text{SO}_{4} = 2 moles \text{Na}^{+}.
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First, we need to find out how many moles of \text{Na}_{2}\text{SO}_{4} are in the sample.
5.63\ \cancel{\text{g}\ \text{Na}_{2}\text{SO}_{4}}\times \frac{1\ \text{mol}\ \text{Na}_{2}\text{SO}_{4}}{142.1\ \cancel{\text{g}\ \text{Na}_{2}\text{SO}_{4}}}= 0.0396 \ \text{mol}\ \text{Na}_{2}\text{SO}_{4}The number of moles of \text{Na}^{+} ions in 0.0396 mol of \text{Na}_{2}\text{SO}_{4} is:
0.0396\ \cancel{\text{mol}\ \text{Na}_{2}\text{SO}_{4}}\times \frac{2\ \text{mol}\ \text{Na}^{+}}{1\ \cancel{\text{mol}\ \text{Na}_{2}\text{SO}_{4}}}= 0.0792 \ \text{mol}\ \text{Na}^{+}■ Quick Check 4.10
How many moles of copper(I) ions, \text{Cu}^{+}, are there in 0.062 g of copper(I) nitrate, \text{CuNO}_{3}?
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