One kind of ammeter measures the current in a wire by measuring the voltage across a precision resistor called a shunt connected in series with the wire. In a particular case, the shunt has resistance R = 0.05 Ω ± 0.05 % nd the voltage across the shunt is V = 1.872 mV What is the current I through

Question

One kind of ammeter measures the current in a wire by measuring the voltage across a precision resistor called a shunt connected in series with the wire. In a particular case, the shunt has resistance [latex] R=0.05 \Omega \pm 0.05 % [/latex] and the voltage across the shunt is V=1.872 mV . What is the current I through the shunt?

Accepted Answer

The current is in the range [latex] I_{\min } \leq I \leq I_{\max }[/latex] , where

[latex] \begin{aligned} &I_{\min }=\frac{V}{R_{\max }}=\frac{1.872 mV }{(0.05 \Omega)(1.0005)}=37.421 mA, \\ &I_{\max }=\frac{V}{R_{\min }}=\frac{1.872 mV }{(0.05) \Omega (0.9995)}=37.459 mA .\end{aligned} [/latex]

Question 2.9: One kind of ammeter measures the current in a wire by measur...

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