Question 19.7: Relating E°cell and K Use the tabulated electrode potentials...

Relating E_{cell}^\circ and K

Use the tabulated electrode potentials to calculate K for the oxidation of copper by H^+ (at 25 °C):

Cu(s) + 2  H^+(aq) \longrightarrow Cu^{2+}(aq) + H_2( g)

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SORT You are given a redox reaction and asked to find K. GIVEN: Cu(s) + 2  H^+(aq) \longrightarrow Cu^{2+}(aq) + H_2( g)

FIND: K

STRATEGIZE Refer to the values of electrode potentials in Table 19.1 to calculate E_{cell}^\circ . Then use Equation 19.6 to calculate K from E_{cell}^\circ .

E_{cell}^\circ =\frac{0.0592  V}{n} log  K  [19.6]

CONCEPTUAL PLAN

E_{an}^\circ ,E_{cat}^\circ \longrightarrow E_{cell}^\circ

 

E_{cell}^\circ \underset{E_{cell}^\circ=\frac{0.0592  V}{n}log  K }{\longrightarrow} K

SOLVE Separate the reaction into oxidation and reduction half-reactions and find the standard electrode potentials for each. Find E_{cell}^\circ by subtracting E_{an} from E_{cat}. SOLUTION

Oxidation

(Anode) Cu(s) \longrightarrow Cu^{2+}(aq) + \cancel{2  e^-}   E° = 0.34  V

Reduction

(Cathode): 2  H^+(aq) + \cancel{2  e^-} \longrightarrow H_2(g)  E° = 0.00  V \\ \overline{ Cu(s) + 2  H^+(aq) \longrightarrow Cu^{2+}(aq) + H_2(g)   E_{cell}^\circ=E_{cat}^\circ -E_{an}^\circ = -0.34  V } 

Calculate K from E_{cell}^\circ . The value of n (the number of moles of electrons) corresponds to the number of electrons that are canceled in the half-reactions. E_{cell}^\circ =\frac{0.0592  V}{n} log  K

 

log  K =E_{cell}^\circ \frac{n}{0.0592  V}

 

log  K = -0.34  \cancel{V} \frac{2}{0.0592  \cancel{V}} =-11.4\underline{8}6

 

K = 10^{-11.4\underline{8}6} =3.3 \times 10^{-12}

CHECK The answer has no units, as expected for an equilibrium constant. The magnitude of the answer is small, indicating that the reaction lies far to the left at equilibrium, as expected for a reaction in which E_{cell}^\circ is negative.

Table 19.1

Standard Electrode Potentials at 25 °C
Reduction Half-Reaction E°(V)
F_2(g) + 2 e^-   \longrightarrow  2 F^-(aq) 2.87
H_2O_2(aq) + 2 H^+(aq) + 2 e^- \longrightarrow 2 H_2O(l) 1.78
PbO_2(s) + 4 H^+(aq) + SO_4{}^{2-}(aq) + 2 e^- \longrightarrow PbSO_4(s) + 2 H_2O(l) 1.69
MnO_4^-(aq) + 4 H^+(aq) + 3 e^- \longrightarrow  MnO_2(s) + 2 H_2O(l) 1.68
MnO_4{}^-(aq) + 8 H^+(aq) + 5 e^- \longrightarrow   Mn^{2 +}(aq) + 4 H_2O(l) 1.51
Au^{3 +}(aq) + 3 e^- \longrightarrow Au(s) 1.50
PbO_2(s) + 4 H^+(aq) + 2 e^- \longrightarrow Pb^{2 +}(aq) + 2 H_2O(l) 1.46
Cl_2(g) + 2 e^- \longrightarrow  2 Cl^-(aq) 1.36
Cr_2O_7{}^{2 -}(aq) + 14 H^+(aq) + 6 e^- \longrightarrow 2 Cr^{3 +}(aq) + 7 H_2O(l) 1.33
O_2(g) + 4 H^+(aq) + 4 e^- \longrightarrow 2 H_2O(l) 1.23
MnO_2(s) + 4 H^+(aq) + 2 e^- \longrightarrow Mn^{2 +}(aq) + 2 H_2O(l) 1.21
IO_3^-(aq) + 6 H^+(aq) + 5 e^- \longrightarrow \frac{1}{2} I_2(aq) + 3 H_2O(l) 1.20
Br_2(l) + 2 e^-    \longrightarrow  2 Br^-(aq) 1.09
VO_2^{+}(aq) + 2 H^+(aq) + e^- \longrightarrow VO^{2 +}(aq) + H_2O(l) 1.00
NO_3{}^{-}(aq) + 4 H^+(aq) + 3 e^-    \longrightarrow NO(g) + 2 H_2O(l) 0.96
ClO_2(g) + e^- \longrightarrow ClO_2{}^-(aq) 0.95
Ag^+(aq) + e^-   \longrightarrow Ag(s) 0.80
Fe^{3 +}(aq) + e^-  \longrightarrow Fe^{2 +}(aq) 0.77
O_2(g) + 2 H^+(aq) + 2 e^- \longrightarrow H_2O_2(aq) 0.70
MnO_4{}^-(aq) + e^- \longrightarrow  MnO_4{}^{2-}(aq) 0.56
I_2(s) + 2 e^-  \longrightarrow  2 I^-(aq) 0.54
Cu^+(aq) + e^- \longrightarrow Cu(s) 0.52
O_2(g) + 2 H_2O(l) + 4 e^-  \longrightarrow 4 OH^-(aq) 0.40
Cu^{2+}(aq) + 2 e^-    \longrightarrow Cu(s) 0.34
SO_4{}^{2 -}(aq) + 4 H^+(aq) + 2 e^- \longrightarrow H_2SO_3(aq) + H_2O(l) 0.20
Cu^{2+}(aq) + e^-     \longrightarrow Cu^+(aq) 0.16
Sn^{4+}(aq) + 2 e^- \longrightarrow Sn^{2 +}(aq) 0.15
2 H^+(aq) + 2 e^- \longrightarrow H_2(g) 0
Fe^{3+}(aq) + 3 e^- \longrightarrow  Fe(s) 0.036
Pb^{2+}(aq) + 2 e^- \longrightarrow  Pb(s) -0.13
Sn^{2+}(aq) + 2 e^- \longrightarrow Sn(s) -0.14
Ni^{2+}(aq) + 2 e^- \longrightarrow Ni(s) -0.23
Cd^{2+}(aq) + 2 e^-  \longrightarrow  Cd(s) -0.40
Fe^{2+}(aq) + 2 e^- \longrightarrow Fe(s) -0.45
Cr^{3+}(aq) + e^- \longrightarrow Cr^{2+}(aq) -0.50
Cr^{3+}(aq) + 3 e^- \longrightarrow Cr(s) -0.73
Zn^{2+}(aq) + 2 e^- \longrightarrow Zn(s) -0.76
2 H_2O(l) + 2 e^- \longrightarrow H_2(g) + 2 OH^-(aq) -0.83
Mn^{2+}(aq) + 2 e^- \longrightarrow Mn(s) -1.18
Al^{3+}(aq) + 3 e^- \longrightarrow  Al(s) -1.66
Mg^{2+}(aq) + 2 e^- \longrightarrow  Mg(s) -2.37
Na^+(aq) + e^- \longrightarrow Na(s) -2.71
Ca^{2+}(aq) + 2 e^-  \longrightarrow  Ca(s) -2.76
Ba^{2+}(aq) + 2 e^- \longrightarrow Ba(s) -2.90
K^+(aq) + e^-  \longrightarrow K(s) -2.92
Li^+(aq) + e^- \longrightarrow Li(s) -3.04

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