Question 5.6: Show that ≤m is a transitive relation.
Show that \leq _{m} is a transitive relation.
The blue check mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.
Learn more on how we answer questions.
Suppose A \leq _{m} B and B \leq _{m} C. Then there are computable functions f and g such that x\in A\Longleftrightarrow f(x) \in B and y\in B\Longleftrightarrow g(y) \in C. Consider the composition function h (x)= g(f(x)). We can build a TM that computes h as follows: First, simulate a TM for f (such a TM exists because we assumed that f is computable) on input x and call the output y. Then simulate a TM for g on y.
The output is h (x)= g(f(x)). Therefore, h is a computable function. Moreover, x\in A \Longleftrightarrow h(x)\in C. Hence A \leq _{m} C via the reduction function h.
Related Answered Questions
Question: 5.30
Verified Answer:
(a) INFINITE_{TM} is a language of ...
Question: 5.28
Verified Answer:
Assume for the sake of contradiction that P is a d...
Question: 5.11
Verified Answer:
Let C = { 〈M〉 | M is a two-tape TM that writes a...
Question: 5.8
Verified Answer:
You need to handle the case where the head is at t...
Question: 5.7
Verified Answer:
Suppose that A\leq _{m} \overline{A}[/latex...
Question: 5.10
Verified Answer:
Let B = {〈M,w〉 | M is a two-tape TM that writes ...
Question: 5.5
Verified Answer:
Suppose for a contradiction that A_{TM}\leq...