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Question 2.4: THE DAYTONA 500 GOAL Apply the basic kinematic equations. PR...

THE DAYTONA 500

GOAL Apply the basic kinematic equations.

PROBLEM A race car starting from rest accelerates at a constant rate of 5.00 \mathrm{~m} / \mathrm{s}^{2}. (a) What is the velocity of the car after it has traveled 1.00 \times 10^{2} \mathrm{ft} ? (b) How much time has elapsed? (c) Calculate the average velocity two different ways.

STRATEGY We’ve read the problem, drawn the diagram in Figure 2.16, and chosen a coordinate system (steps 1 and 2). We’d like to find the velocity v after a certain known displacement \Delta x. The acceleration a is also known, as is the initial velocity v_{0} (step 3, labeling, is complete), so the third equation in Table 2.4 looks most useful for solving part (a). Given the velocity, the first equation in Table 2.4

Table 2.4 equations for Motion in a straight Line Under Constant Acceleration
Equation Information Given by Equation
v = v_0 + at Velocity as a function of time
\Delta_x = v_0 t + \frac{1}{2}at^2 Displacement as a function of time
v^2 = v_0^2 + 2a\Delta x Velocity as a function of displacement
Note: Motion is along the x– axis. At t = 0, the velocity of the particle is v_0.

can then be used to find the time in part (b). Part (c) requires substitution into Equations 2.2

\bar{v} ≡ \frac{Δx}{Δt} = \frac{x_f  –  x_i}{t_f  –  t_i}            [2.2]

and 2.7,

\bar{v} ≡ \frac{v_0 + v}{2}  (for constant α)         [2.7]

respectively.

2.16
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