Question 13.2: The Density of the Earth Using the known radius of the Earth...

The Density of the Earth

Using the known radius of the Earth and that g = 9.80 m/s² at the Earth’s surface, find the average density of the Earth.

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Conceptualize Assume the Earth is a perfect sphere. The density of material in the Earth varies, but let’s adopt a simplified model in which we assume the density to be uniform throughout the Earth. The resulting density is the average density of the Earth.

Categorize This example is a relatively simple substitution problem.

Using Equation 13.5, solve for the mass of the Earth:

g=G \frac{M_E}{R_E{}^2}     (13.5)

M_E=\frac{g R_E{}^2}{G}

Substitute this mass and the volume of a sphere into the definition of density (Eq. 1.1):

\rho \equiv \frac{m}{V}     (1.1)

\begin{aligned}\rho_E & =\frac{M_E}{V_E}=\frac{g R_E{}^2 / G}{\frac{4}{3} \pi R_E{}^3}=\frac{3}{4} \frac{g}{\pi G R_E} \\& =\frac{3}{4} \frac{9.80  m/s^2}{\pi\left(6.674 \times 10^{-11}  N \cdot m^2 /  kg^2\right)\left(6.37 \times 10^6  m\right)}=5.50 \times 10^3  kg/ m^3\end{aligned}

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