Question 7.1: The following currents were recorded under fault conditions ...

The following currents were recorded under fault conditions in a three-phase system:

I_{A} =150\angle 45° A
I_{B} =250\angle 150° A
I_{C} =100\angle 300° A

Calculate the values of the positive, negative, and zero phase sequence components for each line.

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I_{0} =\frac{1}{3} \left(I_{A}+I_{B}+I_{C}\right)
=\frac{1}{3}\left(106.04+j 106.07 +j106.07 -216.51 +j125.00 +50 -j86.6\right)
=52.2\angle 112.7°

I_{+}=\frac{1}{3}\left(I_{A}+\alpha I_{B}+\alpha ^{2}I_{C} \right)=\frac{1}{3}\left(150\angle 45°+250\angle 270°+100\angle 180°\right)
=48.02\angle -87.6°

I_{-}=\frac{1}{3}\left(I_{A}+\alpha ^{2}I_{B}+\alpha I_{C} \right)
=163.21\angle 40.45°

Related Answered Questions

Question: 7.2

Verified Answer:

V_{A}=V_{+}+V_{-}+V_{0} =200...
Question: 7.3

Verified Answer:

The zero sequence network is shown in Figure 7.16.