Question 17.10: The header mentioned in Example 17.9 is to be built with a s...

L_{1} =18 in., H =7.25 in., and h=14 in. Calculate the following:

\frac{L_{1}}{H}=\frac{18}{7.25} =2.48                   C_{1}=C_{2} =1.00

\frac{L_{1}}{h}=\frac{18}{14} =1.29              C_{1} = 0.79 and C_{2} = 0.83.

The strengthening effect applies to the long side only because the length-to-width ratio is less than 2.0. This gives

\left(S_{ b }\right)_{ N }^{\prime}=\left(S_{ b }\right)_{ N } \times C_{1} =(11,020)(0.79)=8710 psi