Question 31.15: The isotope nitrogen-13 has a half-life of 10 min. A sample ...

The isotope nitrogen-13 has a half-life of 10 min. A sample initially contains 8.0 × 10^{10} undecayed nuclei.

a Write down an equation to show how the number undecayed, N, depends on time, t.

b Determine how many nuclei will remain after 10min, and after 20 min .

c Determine how many nuclei will decay during the first 30 min.

The blue check mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.

N = N_{0}  e^{–λt}
b After 10 minutes, half the nuclei will decay, so half will remain undecayed, or 4.0 × 10^{10} After a further 10 minutes, half the remaining
number will decay, leaving one-quarter of the original number, or 2.0 × 10^{10}
c After 30 minutes, three half-lives have elapsed. Number of original nuclei decaying in this time= \frac{1}{2} + \frac{1}{4} + \frac{1}{8} = \frac{7}{8} of total = 7.0 \times 10^{10}

Related Answered Questions

Question: 31.2

Verified Answer:

^{41} _{18}Ar  →  ^{41} _{19}K  +  ^{0}_{-1...