The potential difference across a resistor is measured as 6.0 ± 0.2 V, while the current is measured as 2.4 ± 0.1 A. Calculate the resistance of the resistor and the absolute uncertainty in its measurement.

Question

Accepted Answer

Step 1 Find the percentage uncertainty in each of the quantities:
percentage uncertainty in [latex]p.d. = \frac{0.2}{6.0} × 100[/latex]% = 3.3%
percentage uncertainty in current [latex]= \frac{0.1}{2.4} × 100[/latex]% = 4.2%
Step 2 Add the percentage uncertainties.
sum of uncertainties = (3.3 + 4.2)% = 7.5%
Step 3 Calculate the resistance value and find the absolute uncertainty
[latex]R = \frac{V}{I} = \frac{6.0}{2.4} = 2.5 Ω[/latex]
7.5% of 2.5 = 0.1875 ≈ 0.2 Ω
The resistance of the resistor is 2.5 ±0.2 Ω.

Question P2.WE.2: The potential difference across a resistor is measured as 6....

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