Question 16.7: The preliminary design of an axial flow compressor is to be ...

The preliminary design of an axial flow compressor is to be based upon a simplified consideration of the mean diameter conditions. Suppose that the characteristics of a repeating stage of such a design are as follows:

Stagnation temperature rise (ΔTst \Delta T_{s t} ) 30 K
Degree of reaction ( Λ \Lambda ) 0.6
Flow coefficienty (Vf/U V_{f} / U ) 0.5
Blade speed (U U ) 300 m/s

Assuming constant axial velocity across the stage and equal absolute velocities at inlet and outlet, determine the blade angles of the rotor for a shock free flow. (cp c_{p} for air = 1005 J/kg K).

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Specific work input       w=1005×30 J/kg w=1005 \times 30 \mathrm{~J} / \mathrm{kg}

From Eq. (16.17)

ΔTst=ΔTs=UVfcp(tanβ1tanβ2) \Delta T_{s t}=\Delta T_{s}=\frac{U V_{f}}{c_{p}}\left(\tan \beta_{1}-\tan \beta_{2}\right)                 (16.17)

1005×30=(300)2×(0.5)(tanβ1tanβ2) 1005 \times 30=(300)^{2} \times(0.5)\left(\tan \beta_{1}-\tan \beta_{2}\right)

Or     tanβ1tanβ2=0.67 \tan \beta_{1}-\tan \beta_{2}=0.67

Again from Eq. (16.24),

Λ=Vf2U(tanβ1+tanβ2) \Lambda=\frac{V_{f}}{2 U}\left(\tan \beta_{1}+\tan \beta_{2}\right)                   (16.24)

0.6=0.52(tanβ1+tanβ2) 0.6=\frac{0.5}{2}\left(\tan \beta_{1}+\tan \beta_{2}\right)

 

tanβ1+tanβ2=2.4  \tan \beta_{1}+\tan \beta_{2}=2.4 

The above two equations give

β1=56.92,β2=40.86 \beta_{1}=56.92^{\circ}, \quad \beta_{2}=40.86^{\circ}

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