Question 7.6: The roof of an industrial building is to be supported by wid...
The roof of an industrial building is to be supported by wide-flange beams spaced 1.5 m on centers across an 8 m span, as sketched in Figure 7–18. The roof will be a poured concrete slab, 100 mm thick. The design live load on the roof is 8.0 kN/m². Specify a suitable IPE steel shape that will limit the stress in the beam to the design stress for ASTM A36 struc-tural steel using the AISC specification.

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Objective Specify a suitable wide-flange beam.
Given Loading pattern in Figure 7–19; design stress from AISC specifications for ASTM A36 structural steel
Analysis Design procedure A from this section will be used.
Results Step 1. We must first determine the load on each beam of the roof structure.
Dividing the load evenly among adjacent beams would result in each beam carrying a 1.5 m wide portion of the roof load. In addition to the 8 kN/m² live load, the weight of
the concrete slab offers a sizeable load. In Section 2–10, we find that the concrete weighs 23.6 kN/m³. Then, each square meter of the roof, 100 mm thick (0.10 m), would have a volume of
V = (1.0 m)(1.0 m)(0.10 m) = 0.10 m³
The weight of each square meter would then be
W = V(23.6 kN/m³)=(0.10 m³)(2.36 kN/m³) = 2.36 kN
This is called the “dead load.” Then, adding the live load, the total loading due to the roof is 10.36 kN/m². Now, notice that each meter of length of the beam carries 1.5 m² of the roof. Therefore, the load on the beam is a uniformly distributed load of 15 540 N/m. Figure 7–19 shows the loaded beam and the shearing force and bending moment diagrams. The maximum bending moment is 124 320 N m at the middle of the length of the beam.
Steps 2 and 3. Table 7–2 calls for the design stress to be
TABLE 7–2 Design stresses from selected codes: Bending stresses—Static loads on building-like structures. | ||
Structural steel (AISC): | ||
σ_{d} = s_{y} /1.5 = 0.66s_{y} | ||
Aluminum (AA): | ||
σ_{d} = s_{y} /1.65 = 0.66s_{y} | or σ_{d} = s_{u}/1.95 = 0.51s_{u} | whichever is lower |
σ_{d} = 0.66s_{y}
From Appendix A–12, the yield strength of ASTM A36 structural steel is 248 MPa. Then,
A–12 Properties of structural steels .^{a} | |||||
Ultimate strength, s_{u}^{a} | Yield strength, s_{y}^{a} | ||||
Material ASTM No. and products | ksi | Mpa | ksi | Mpa | Percent elongation in 2 in. |
A36—carbon steel; available in shapes,plates, and bars | 58 | 400 | 36 | 248 | 21 |
A 53—Grade B pipe | 60 | 414 | 35 | 240 | 23 |
A242—HSLA, corrosion resistant; available in shapes, plates, and bars | |||||
≤ \frac{3}{4} in. thick | 70 | 483 | 50 | 345 | 21 |
1 \frac{1}{2} in. thick | 67 | 462 | 46 | 317 | 21 |
1 \frac{1}{2} to 4 in. thick | 63 | 434 | 42 | 290 | 21 |
A500—Cold-formed structural tubing | |||||
Round, Grade B | 58 | 400 | 42 | 290 | 23 |
Round, Grade C | 62 | 427 | 46 | 317 | 21 |
Round, Grade B | 58 | 400 | 46 | 317 | 23 |
Round, Grade C | 62 | 427 | 50 | 345 | 21 |
A501—Hot-formed structural tubing, round or shaped | 58 | 400 | 36 | 248 | 23 |
A514—Quenched and tempered alloy steel; available in plate only | |||||
≤ 2\frac{1}{2} in. thick | 110 | 758 | 100 | 680 | 18 |
2\frac{1}{2} to 6 in. thick | 100 | 690 | 90 | 620 | 16 |
A572—HSLA columbium–vanadium steel; available in shapes, plates, and bars | |||||
Grade 42 | 60 | 414 | 42 | 290 | 24 |
Grade 50 | 65 | 448 | 50 | 345 | 21 |
Grade 60 | 75 | 517 | 60 | 414 | 18 |
Grade 65 | 80 | 552 | 65 | 448 | 17 |
A913—HSLA, grade 65; available in shapes only | 80 | 552 | 65 | 448 | 17 |
A992—HSLA; available in W-shapes only | 65 | 448 | 50 | 345 | 21 |
^{a} Minimum values; may range higher.
HSLA, an abbreviation for high-strength, low-alloy steel.
The American Institute of Steel Construction specifies E = 29 × 10^6 psi (200 GPa) for structural steel.
σ_{d} = 0.66s_{y} = 0.66(248 MPa) = 164 MPa
Step 4. In order to select an IPE shape beam, the required minimum section modulus must be calculated.
σ_{d} = \frac{M}{S_{min}}
S_{min} = \frac{M}{σ_{d}} = \frac{124 320 N·m \left\lgroup \frac{1000 mm}{1 m} \right\rgroup }{164 N/mm²} = 7.58 \times 10^{5} mm^{3}
Step 5. This step does not apply in this problem.
Step 6. A beam must be found from Appendix A–7(e), which has a value of S greater than 7.58 \times 10^{5} mm^{3} . The lightest IPE shape is:
IPE 360×170 : S = 9.036 \times 10^{5} mm^{3}
Comment In the final design of the structure, lateral bracing would be required as defined in Reference 5. Also, deflection of the beam should be checked using the methods described in Chapter 9.

