The vertical pressure vessel shown in Figure 16.4 has the following design values: Total weight=252,000 lbs T =0.088 s (obtained from Example 16.3 in Section 16.2.2) Ip =1.0 Location: vicinity of Portland, Oregon. Base of the vessel is at ground level (z =0.0). Site class is B (rock foundation):

Question

The vertical pressure vessel shown in Figure 16.4 has the following design values:

Total weight=252,000 lbs

T =0.088 s (obtained from Example 16.3 in Section 16.2.2)

[latex] I_{p}[/latex] =1.0

Location: vicinity of Portland, Oregon.

Base of the vessel is at ground level (z =0.0).

Site class is B (rock foundation): [latex] F_{a}[/latex] =1.0

Determine the earthquake lateral load using the ASD method and

a) Equation (16.2)

[latex] F_{ p }=0.4 I_{ p } S_{ DS } W_{ p }(1+2 z / h)[/latex] (16.2)

b) Equation (16.4).

[latex] F_{ p }=0.4 I_{ p } S_{ a } W_{ p }(1+2 z / h)[/latex] (16.4)

Accepted Answer

a)

[latex] S_{s}[/latex] = 0.9 from Figure 16.1.

From Eq. (16.3),

[latex] S_{ DS }=0.667 F_{ a } S_{ s } [/latex] (16.3)

[latex] S_{DS}[/latex] = 0.667(1)(0.9) = 0.6

From Eq. (16.2),

[latex] F_{ p }=0.4 I_{ p } S_{ DS } W_{ p }(1+2 z / h)[/latex] (16.2)

[latex] F_{p}[/latex] = (2∕3)[0.4(1)(0.6)(252,000)(1)]

= 0.16(252,000)

= 40,320 lbs = 1344 lbs∕ft of length.

[latex] S_{1}[/latex] = 0.5 from Figure 16.2

[latex] T_{L}[/latex] = 16 from Figure 16.3

[latex] T_{s}[/latex] = 0.5∕0.9 = 0.556

[latex] T_{o}[/latex] = 0.2(0.556) = 0.111.

Since T is less than [latex] T_{o}[/latex], Eq. (16.5a) is used

[latex] S_{ a }=S_{ DS }\left(0.4+0.6 T / T_{ o }\right) \quad T

[latex] S_{a}[/latex] = (0.6)[0.4 + 0.6(0.088)∕0.111] = 0.525.

From Eq. (16.4),

[latex] F_{ p }=0.4 I_{ p } S_{ a } W_{ p }(1+2 z / h)[/latex] (16.4)

[latex] F_{ p }[/latex] = (2∕3)[0.4(1)(0.525)(252,000)(1)]

= 0.14(252,000)

= 35,280 lbs = 1176 lbs∕ft.

A software program and maps may be accessed for determining the values of [latex] S_{s}[/latex] and [latex] S_{1}[/latex] more accurately at the USGS Website “http://earthquake.usgs.gov/hazards/ designmaps/” based on the address of the vessel location.

Question 16.1: The vertical pressure vessel shown in Figure 16.4 has the fo...

Related Answered Questions

Verified Answer:

A tall vessel is constructed with a cylindrical shell and two hemispherical heads. The vessel is designed for full vacuum (15 psi external pressure) at a design temperature of 550 °F. The material is SA-516 Grade 60. There is no corrosion allowance required. The vessel has 10 ft 0 in. inside ...

Verified Answer:

The vessel given in Example 16.3 is to be constructed from SA-516 Grade 60 material and designed for 475 psi at 650 °F. The weld joint efficiency is E =1.0. What are the total longitudinal stresses on both the windward and leeward sides at the support line? What are the allowable tensile and ...

Verified Answer:

The vessel described in Example 16.7 is to be supported at the lower shell-to-head junction. What are the longitudinal stresses in the shell above and below the support line? The internal pressure is 225 psi. Let the bending moment Me =864,000 in.-lb. ...

Verified Answer:

For the vessel described in Example 16.7, determine the fluid pressure head for containing fluid at 35 lb/ft^3 and for hydrostatic testing using water at 62.4 lb/ft^3. ...

Verified Answer:

A vertical vessel with a cylindrical shell and hemispherical heads is installed inside a building. The shell has 5 ft inside diameter and 0.5 in. nominal thickness, and is 30 ft from tangent to tangent. The vessel contains a fluid at 35 lbs/ft^3. Determine the total longitudinal stress in the ...

Verified Answer:

Determine if the vessel described in Example 16.4 is adequate to resist vortex shedding and ovalling vibration. ...

Verified Answer:

What is the overturning moment due to the lateral wind forces assuming that the vessel is supported at the lower shell-to-head junction for the vessel mentioned in Example 16.4. ...

Verified Answer:

A vertical vessel has the dimensions shown in Figure 16.4. The skirt weighs 12,000 lbs or 100 lbs/in., and the weight of the shell, heads, and fluid is 240,000 lbs or 1000 lbs/in. Moment of inertial of the shell is 2.074 × 10^6 in.^4, and moment of inertial of the skirt is 0.518 × 10^6 in.^4. ...

Verified Answer:

Find the fundamental natural frequency and period of vibration of a cantilever beam of uniform cross section, Figure 16.6. Let L=length, in., EI=constant, lbs-in.^2, w=uniform distributed weight, lbs/in. of length, m = mass=w/386.4, lbs-s^2/in.^2 ...

Verified Answer: