Question 13.21: Total Power Transferred to the Rotor from Stator The torque ...

To calculate the synchronous speed, use Equation (13.39):

N=\frac{120 \cdot f}{P}     (13.39)

N_{s}=\frac{120 \times f}{P}=\frac{120 \times 60}{6}=1200 rpm

Next, the full-load slip corresponds to:

Thus:

N=(1-s) N_{s}=1119.6 rpm

Now, using Equation (13.52):

Therefore, the total power available to the rotor is:

P_{r}=P_{m}+P_{c}=17,656+500=18.16 KkW