Subscribe $4.99/month

Un-lock Verified Step-by-Step Experts Answers.

Find the Source, Textbook, Solution Manual that you are looking for in 1 click.

Our Website is free to use.
To help us grow, you can support our team with a Small Tip.

All the data tables that you may search for.

Need Help? We got you covered.

For Arabic Users, find a teacher/tutor in your City or country in the Middle East.

Products

Find the Source, Textbook, Solution Manual that you are looking for in 1 click.

For Arabic Users, find a teacher/tutor in your City or country in the Middle East.

Need Help? We got you covered.

Chapter 5

Q. 5.2

Use the simple model for solar radiation under cloudless skies (p. 64) to estimate the direct, diffuse, and total solar irradiance on a horizontal surface at 45°N at local solar noon on 21 June for three values of aerosol optical thickness, 0.05, 0.20, 0.40. Assume that the optical thickness for molecular attenuation is 0.30.

Step-by-Step

Verified Solution

At solar noon \psi =\phi -\delta =45.0-23.5=21.5 . Hence m = sec 21.5 = 1.075. Then S_{p} = 1366 \exp (-0.30\times 1.075) (\exp -(1.075\times \tau_{a} )) =990\exp (-1.075\times \tau_{a} ) and S_{s} = S_{p} \cos \psi .

Diffuse radiation is calculated as S_{d} = 0.3 \times 1366 \times \cos 21.5(1-\exp (-(\tau_{m} + \tau_{a} )\times 1.075)) , and S_{t} =S_{s} +S_{d} . The table shows results of the calculations in W m^{-2} for the three values of τ_{a}.

τ_{a} S_{p}  S_{s}   S_{d} S_{t}
0.05   941 875   118 993
0.20 802 746 160 906
0.4  644  599 202 801