Question 6.16: Use VSEPR theory to predict the shape of the molecule SiCI4.

Use VSEPR theory to predict the shape of the molecule SiCl_{4}.

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ANALYZE THE PROBLEM Given Need Connect
SiCl_{4} shape Lewis structure, electron groups, bonded atoms

STEP 1   Draw the Lewis structure. Using 32 e^{-} , we draw the bonds and lone pairs for the Lewis strucntre of SiCl_{4}.

Name of Element  Silicon Chlorine
Symbol of Element Si Cl
Atoms of Element 1 Si 4 Cl
Valence Electrons 4 e^{-} 7 e^{-}
Total Electrons 1(4  e^{-})                                                             +                            4(7  e^{-}) = 32  e^{-}
\begin{array}{r c}& {}_{\bullet }^{\bullet } \overset{\bullet \bullet }{\underset{\bullet \bullet }{Cl_{\bullet }^{\bullet }}} \overset{{}_{\bullet }^{\bullet } \overset{\bullet \bullet }{\underset{\bullet \bullet }{Cl_{\bullet }^{\bullet }}}}{\underset{{}_{\bullet }^{\bullet } \overset{\bullet \bullet }{\underset{\bullet \bullet }{Cl_{\bullet }^{\bullet }}}}{Si_{\bullet }^{\bullet }}} \overset{\bullet \bullet }{\underset{\bullet \bullet }{Cl_{\bullet }^{\bullet }}}\end{array}

STEP 2   Arrange the electron groups around the central atom to minimize repulsion. In the Lewis structure of SiCl_{4}, there are four electron groups around the central Si atom. To minimize repulsion, the electron-group geometry would be tetrahedral.

STEP 3   Use the atoms bonded to the central atom to determine the shape. Because the central Si atom has four bonded pairs and no lone pairs of electrons, the SiCl_{4} molecule has a tetrahedral shape.

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