Using Appendix 3B, calculate the following equilibrium constants (a) [latex]\mathrm{K}_{\mathrm{b}}[/latex] for pyridine, [latex]\mathrm{C}_{5} \mathrm{H}_{5} \mathrm{~N}[/latex] (b) [latex]K_{\mathrm{b}}[/latex] for dihydrogen phosphate, [latex]\mathrm{H}_{2} \mathrm{PO}_{4}^{-}[/latex]

(a) [latex]K_{\mathrm{b}, \mathrm{C}_{5} \mathrm{H}_{5} \mathrm{~N}}=\frac{K_{\mathrm{w}}}{K_{\mathrm{a}, \mathrm{C}_{5} \mathrm{H}_{5} \mathrm{NH}^{+}}}=\frac{1.00 \times 10^{-14}}{5.90 \times 10^{-6}}=1.69 \times 10^{-9}[/latex] (b) [latex]K_{\mathrm{b}, \mathrm{H}_{2} \mathrm{PO}_{4}^{-}}=\frac{K_{\mathrm{w}}}{K_{\mathrm{a}, \mathrm{H}_{3} \mathrm{PO}_{4}}}=\frac{1.00 \times 10^{-14}}{7.11 \times 10^{-3}}=1.41 \times 10^{-12}[/latex]

Question 6.3: Using Appendix 3B, calculate the following equilibrium const...

Modern Analytical Chemistry

Using Appendix 3B, calculate the following equilibrium constants

(a) $\mathrm{K}_{\mathrm{b}}$ for pyridine, $\mathrm{C}_{5} \mathrm{H}_{5} \mathrm{~N}$

(b) $K_{\mathrm{b}}$ for dihydrogen phosphate, $\mathrm{H}_{2} \mathrm{PO}_{4}^{-}$

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