Question 11.9: Using the Berthelot equation of state given in Example 11.8,...
Using the Berthelot equation of state given in Example 11.8, determine an equation for the isothermal variation in the constant volume specific heat with volume change.
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From Eq. (11.28) we have what we seek,
(\frac{∂c_v}{∂v})_T = T(\frac{∂^2p}{∂T^2 })_v
and from Example 11.8, the Berthelot equation of state can be written as
p = \frac{RT}{v −b} – \frac{a}{Tv^2}
so that
(\frac{∂p}{∂T})_v = \frac{R}{v −b} + \frac{a}{T^2v^2}
and
(\frac{∂^2p}{∂T^2 })_v = – \frac{2a}{T^3v^2 }
then,
(\frac{∂c_v}{∂v})_T = −\frac{2a}{T^2v^2}
and, to find an explicit c_v = c_v (T, v ) equation, the preceding equation can be integrated from a reference state specific volume v_o to give
c_v = − \frac{2a}{T^2} \int_{v_0}^{v} \frac{dv}{v^2} = 2a(v_0 − v)/(T^2v_0v) + f (T)
where f (T) is a function of integration. Note that c_v is independent of v only in the case where a = 0 in the Berthelot equation of state.