Question 6.8: Using the ladder diagram in Figure 6.7, predict the result o...

The predominance regions for Ca^{2+} and Mg(EDTA)^{2–} do not overlap, therefore, the reaction

Ca^{2+} + Mg(EDTA)^{2–} \rightleftharpoons Mg^{2+} + Ca(EDTA)^{2–}

will take place. Since there is an excess of Ca^{2+}, the composition of the final solution is approximately

Moles Ca^{2+} = 0.080 – 0.060 = 0.020 mol
Moles Ca(EDTA)^{2–} = 0.060 mol

Moles Mg^{2+} = 0.060 mol
Moles Mg(EDTA)^{2–} = 0 mol