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Question 5.12: Water flows at a velocity of 1.417 m/s. A differential gauge...

Water flows at a velocity of 1.417 m/s. A differential gauge which contains a liquid of specific gravity 1.25 is attached to a Pitot-static tube. What is the deflection of the gauge fluid? (Assume the coefficient of the tube to be 1).

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We know from Eq. (5.72)

 

V=C \sqrt{2 \Delta p / \rho} (5.72)

 

V=C \sqrt{2 g(\Delta p / \rho g)}

 

Therefore, for the present case,

 

1.417=1.00 \sqrt{2 \times 9.81(\Delta p / \rho g)}

 

Hence, \Delta p / \rho g=0.1023 m of water

 

From the manometric equation of the differential gauge,

 

0.1023=(1.25-1) h

 

which gives the deflection of the gauge h = 0.409 m = 409 mm

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