Question 10.12: Which of the organic acids in Table 10.2 would be the most a...

Which of the organic acids in Table 10.2 would be the most appropriate for preparing a pH 4.15 buffer solution?
ANALYSIS The pH of the buffer solution depends on the pK_a of the weak acid. Remember that pK_a = – \log(K_a).

 

ACID \pmb{K_a} ACID \pmb{K_a}
Hydrofluoric acid (HF) 3.5 \times 10^{-4} Polyprotic acids
Hydrocyanic acid (HCN) 4.9 \times 10^{-10} Sulfuric acid
Ammonium ion (NH_4  ^+) 5.6 \times 10^{-10} H_2SO_4 Large
HSO_4  ^- 1.2 \times 10^{-2}
Organic acids Phosphoric acid
Formic acid (HCOOH) 1.8 \times 10^{-4} H_3PO_4 7.5 \times 10^{-3}
Acetic acid (CH_3COOH) 1.8 \times 10^{-5} H_2PO_4  ^- 6.2 \times 10^{-8}
Propanoic acid (CH_3CH_2COOH) 1.3 \times 10^{-5} HPO_4  ^{2-} 2.2 \times 10^{-13}
Carbonic acid
Ascorbic acid (vitamin C) 7.9 \times 10^{-5} H_2CO_3 4.3 \times 10^{-7}
HCO_3  ^- 5.6 \times 10^{-11}
The blue check mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.

The K_a and pK_a values for the four organic acids in Table 10.2 are tabulated below. The ascorbic acid (pK_a = 4.10) will produce a buffer solution closest to the desired pH of 4.15.

\begin{matrix} \underline{  \hspace{30 pt}  \pmb{ORGANIC ACID                                        K_a               pK_a} } \\ \begin{matrix} Formic acid (HCOOH) & 1.8 \times 10^{-4} & 3.74 \\ Acetic acid (CH_3COOH) & 1.8 \times 10^{-5} & 4.74 \\ Propanoic acid (CH_3CH_2COOH) & 1.3 \times 10^{-5} & 4.89 \\ Ascorbic acid (vitamin C) & 7.9 \times 10^{-5} & 4.10 \end{matrix} \end{matrix}

Related Answered Questions

Question: 10.8

Verified Answer:

Since HCl is a strong acid (Table 10.1), it is 100...