Question 5.SP.16: Wine is produced by the fermentation of grapes. In fermentat...
Wine is produced by the fermentation of grapes. In fermentation, the carbohydrate glucose (C_{6}H_{12}O_{6}) is converted to ethanol and carbon dioxide according to the given balanced equation. How many grams of ethanol (C_{2}H_{6}O, molar mass 46.07 g/mol) are produced from 5.00 mol of glucose?
\begin{matrix}C_{6}H_{12}O_{6}(aq) & \longrightarrow & 2C_{2}H_{6}O(aq) & +& 2 CO_{2}(g) \\ \text{glucose} & & \text{ethanol}& & \end{matrix}
[1] Convert the number of moles of reactant to the number of moles of product using a mole–mole conversion factor.
• Use the coefficients in the balanced chemical equation to write mole–mole conversion factors for the two compounds—one mole of glucose (C_{6}H_{12}O_{6})\text{ forms two moles of ethanol }(C_{2}H_{6}O).
• Multiply the number of moles of reactant (glucose) by the conversion factor to give the number of moles of product (ethanol).
[2] Convert the number of moles of product to the number of grams of product using the product’s molar mass.
• Use the molar mass of the product (C 2H 6O, molar mass 46.07 g/mol) to write a conversion factor.
• Multiply the number of moles of product (from step [1]) by the conversion factor to give the number of grams of product.
